annameghan
annameghan annameghan
  • 03-10-2017
  • Mathematics
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Respuesta :

liemonder liemonder
  • 03-10-2017
[tex] \sqrt[5]{x} = x^{\frac{1}{5}}\\ \\ \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} =\\ x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}=\\ x^{\frac{4}{5}}[/tex]

so it is the last option
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