beatzenriquez1 beatzenriquez1

04-06-2017
Mathematics

contestada

What is the cube root of -1,000p12q3

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jdoe0001 jdoe0001

04-06-2017

[tex]\bf \sqrt[3]{-1000p^{12}q^3}\qquad \begin{cases} -1000= -10\cdot -10\cdot -10\\ \qquad\qquad (-10)^3\\ p^{12}=p^{4\cdot 3}\\ \qquad (p^4)^3 \end{cases}\implies \sqrt[3]{(-10)^3(p^4)^3q^3} \\\\\\ -10p^4q[/tex]

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kanimesongbird03 kanimesongbird03

02-03-2020

Answer:

-10p4q

Step-by-step explanation:

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