Answer:
81.1 m
Explanation:
Given:
x₀ = 0 m
y₀ = y = 0 m
v₀ₓ = 29.5 cos 33.0° m/s
v₀ᵧ = 29.5 sin 33.0° m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find:
x
First, find the time it takes to land.
y = y₀ + v₀ᵧ t + ½ aᵧt²
0 = 0 + (29.5 sin 33.0) t - 4.9 t²
t = (29.5 sin 33.0) / 4.9
t = 3.28 s
Now in the x direction:
x = x₀ + v₀ₓ t + ½ aₓt²
x = 0 + (29.5 cos 33.0) (3.28) + 0
x = 81.1 m
The outfielder was 81.1 meters away.
